What is the antipode of Cerro de Pasco, Peru?

The antipode of Cerro de Pasco, Peru (-10.66748°, -76.25668°) is located near Sihanoukville, Cambodia (10.60932°, 103.52958°). The antipodal distance is approximately 24.26 km.

What is on the opposite side of the world from Cerro de Pasco?

On the exact opposite side of the Earth from Cerro de Pasco, Peru, you would find a point in the ocean or land near Sihanoukville, Cambodia. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Cerro de Pasco, Peru

The antipode of Cerro de Pasco, Peru is located near Sihanoukville, Cambodia. The exact antipodal point is at coordinates 10.6093°, 103.5296°, which is approximately 24.26 km from Sihanoukville.

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About the Antipode of Cerro de Pasco

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Cerro de Pasco, Peru (population: 58,899), located at coordinates -10.6675°, -76.2567°, the antipodal point falls near Sihanoukville, Cambodia (population: 73,036).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (-10.6675° becomes 10.6675°)
Longitude: Add or subtract 180° (-76.2567° becomes 103.5296°)

The exact antipodal coordinates for Cerro de Pasco are 10.6675°, 103.7433°.

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Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.