What is the antipode of Sihanoukville, Cambodia?

The antipode of Sihanoukville, Cambodia (10.60932°, 103.52958°) is located near Cerro de Pasco, Peru (-10.66748°, -76.25668°). The antipodal distance is approximately 24.26 km.

What is on the opposite side of the world from Sihanoukville?

On the exact opposite side of the Earth from Sihanoukville, Cambodia, you would find a point in the ocean or land near Cerro de Pasco, Peru. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Sihanoukville, Cambodia

The antipode of Sihanoukville, Cambodia is located near Cerro de Pasco, Peru. The exact antipodal point is at coordinates -10.6675°, -76.2567°, which is approximately 24.26 km from Cerro de Pasco.

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About the Antipode of Sihanoukville

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Sihanoukville, Cambodia (population: 73,036), located at coordinates 10.6093°, 103.5296°, the antipodal point falls near Cerro de Pasco, Peru (population: 58,899).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (10.6093° becomes -10.6093°)
Longitude: Add or subtract 180° (103.5296° becomes -76.2567°)

The exact antipodal coordinates for Sihanoukville are -10.6093°, -76.4704°.

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Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.