What is the antipode of Tacloban, Philippines?

The antipode of Tacloban, Philippines (11.24333°, 125.00472°) is located near Sinop, Brazil (-11.86417°, -55.5025°). The antipodal distance is approximately 88.19 km.

What is on the opposite side of the world from Tacloban?

On the exact opposite side of the Earth from Tacloban, Philippines, you would find a point in the ocean or land near Sinop, Brazil. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Tacloban, Philippines

The antipode of Tacloban, Philippines is located near Sinop, Brazil. The exact antipodal point is at coordinates -11.8642°, -55.5025°, which is approximately 88.19 km from Sinop.

Try another location →
Browse all antipodal cities →

About the Antipode of Tacloban

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Tacloban, Philippines (population: 242,089), located at coordinates 11.2433°, 125.0047°, the antipodal point falls near Sinop, Brazil (population: 116,013).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (11.2433° becomes -11.2433°)
Longitude: Add or subtract 180° (125.0047° becomes -55.5025°)

The exact antipodal coordinates for Tacloban are -11.2433°, -54.9953°.

Explore More Antipodes

Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.