What is the antipode of Temuco, Chile?

The antipode of Temuco, Chile (-38.73965°, -72.59842°) is located near Shizuishan, China (39.23333°, 106.76944°). The antipodal distance is approximately 77.48 km.

What is on the opposite side of the world from Temuco?

On the exact opposite side of the Earth from Temuco, Chile, you would find a point in the ocean or land near Shizuishan, China. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Temuco, Chile

The antipode of Temuco, Chile is located near Shizuishan, China. The exact antipodal point is at coordinates 39.2333°, 106.7694°, which is approximately 77.48 km from Shizuishan.

Try another location →
Browse all antipodal cities →

About the Antipode of Temuco

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Temuco, Chile (population: 238,129), located at coordinates -38.7396°, -72.5984°, the antipodal point falls near Shizuishan, China (population: 136,570).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (-38.7396° becomes 38.7396°)
Longitude: Add or subtract 180° (-72.5984° becomes 106.7694°)

The exact antipodal coordinates for Temuco are 38.7396°, 107.4016°.

Explore More Antipodes

Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.