What is the antipode of Tumaco, Colombia?

The antipode of Tumaco, Colombia (1.79112°, -78.79275°) is located near Sungai Penuh, Indonesia (-2.0561°, 101.3913°). The antipodal distance is approximately 35.75 km.

What is on the opposite side of the world from Tumaco?

On the exact opposite side of the Earth from Tumaco, Colombia, you would find a point in the ocean or land near Sungai Penuh, Indonesia. This is calculated by inverting the latitude and adding/subtracting 180° from the longitude.

Antipode of Tumaco, Colombia

The antipode of Tumaco, Colombia is located near Sungai Penuh, Indonesia. The exact antipodal point is at coordinates -2.0561°, 101.3913°, which is approximately 35.75 km from Sungai Penuh.

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About the Antipode of Tumaco

An antipode is the point on Earth's surface that is diametrically opposite to a given location. For Tumaco, Colombia (population: 86,713), located at coordinates 1.7911°, -78.7927°, the antipodal point falls near Sungai Penuh, Indonesia (population: 97,770).

How is the Antipode Calculated?

To find the antipode of any location:

Latitude: Invert the sign (1.7911° becomes -1.7911°)
Longitude: Add or subtract 180° (-78.7927° becomes 101.3913°)

The exact antipodal coordinates for Tumaco are -1.7911°, 101.2073°.

Explore More Antipodes

Curious about other cities? Check out our complete list of 1,000 antipodal city pairs, ranked by proximity. Or use the Antipode Finder to search any location on Earth.